Question

How do you solve `2sinx=sqrt3`?

Answer 1

`(2pi)/3+2kpi, pi/3+2kpi` where `kinZZ`

Explanation:

`3sin(x)=sqrt3 rarr sin(x)=sqrt3/2`

`sin(x)=sqrt3/2` at `(2pi)/3+2kpi, pi/3+2kpi` where `kinZZ`