How do you solve $2 x - 1 < 7$ $2x - 1< 7$ ?

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Answer 1 · 2017-07-26T01:09:16

See a solution process below:

Step 1) Add $1$ $color(red)(1)$ to each side of the inequality to isolate the $x$ $x$ term while keeping the inequality balanced:

$2 x - 1 + 1 < 7 + 1$ $2x - 1 + color(red)(1) < 7 + color(red)(1)$

$2 x - 0 < 8$ $2x - 0 < 8$

$2 x < 8$ $2x < 8$

Step 2) Divide each side of the inequality by $2$ $color(red)(2)$ to solve for $x$ $x$ while keeping the inequality balanced:

$\frac{2 x}{2} < \frac{8}{2}$ $(2x)/color(red)(2) < 8/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) < 4$

$x < 4$

How do you solve 2x - 1< 72x−1<72x - 1< 7?