How do you solve #2x²-17x=9#?

1 Answer
Aug 5, 2016

Answer:

-1/2 and 9

Explanation:

Solving by the new Transforming Method (Socratic Search).
#y = 2x^2 - 17x - 9 = 0#
Transformed equation: #y' = x^2 - 17x - 18 = 0#
Method. Find the 2 real roots of y', then divide them by a = 2.
Since a - b + c = 0, use shortcut. Two real roots are: -1 and #-c/a = 18#.
Back to original equation y --> its 2 real roots are: #x1 = -1/2# and
#x2 = 18/2 = 9#.