# How do you solve 2x^2 + 10x + 12 = 0 using the quadratic formula?

Mar 15, 2016

${x}_{1} = - 3$
${x}_{2} = - 2$

#### Explanation:

$2 {x}^{2} + 10 x + 12 = 0$
$a {x}^{2} + b x + c = 0$

x_"1,2"=(-b±sqrt(b^2-4*a*c))/(2*a)

${x}_{1} = \frac{- 10 - \sqrt{100 - 4 \cdot 2 \cdot 12}}{2 \cdot 2}$
${x}_{1} = \frac{- 10 - \sqrt{4}}{4}$
${x}_{1} = \frac{- 10 - 2}{4}$
${x}_{1} = - \frac{12}{4} \text{ } {x}_{1} = - 3$

${x}_{2} = \frac{- 10 + \sqrt{100 - 4 \cdot 2 \cdot 12}}{2 \cdot 2}$
${x}_{2} = \frac{- 10 + 2}{4}$

${x}_{2} = - \frac{8}{4}$
${x}_{2} = - 2$