Question

How do you solve `2x^2 - 12x + 18 = 32`?

Answer 1

x = -1 and x = 7

Explanation:

`y = 2x^2 - 12x - 14 = 0`
`y = 2(x^2 - 6x - 7) = 0`
Solve the quadratic equation in parentheses.
Since a - b + c = 0, use shortcut. The 2 real roots are: - 1 and
`-c/a = 7.`