# How do you solve 2x^2 - 12x + 18 = 32?

May 6, 2016

x = -1 and x = 7

#### Explanation:

$y = 2 {x}^{2} - 12 x - 14 = 0$
$y = 2 \left({x}^{2} - 6 x - 7\right) = 0$
Solve the quadratic equation in parentheses.
Since a - b + c = 0, use shortcut. The 2 real roots are: - 1 and
$- \frac{c}{a} = 7.$