# How do you solve 2x^2-13x-7=0?

Jun 4, 2016

$x = - \frac{1}{2} \mathmr{and} x = 7$

#### Explanation:

The trinomial $2 {x}^{2} - 13 x - 7 = 0$ can be factored

$\left(2 x + 1\right) \left(x - 7\right) = 0$

Now set each factor equal to zero

$2 x + 1 = 0$

$2 x \cancel{+ 1} \cancel{- 1} = 0 - 1$

$2 x = - 1$

$\frac{\cancel{2} x}{\cancel{2}} = - \frac{1}{2}$

$x = - \frac{1}{2}$

and $x - 7 = 0$

$x \cancel{- 7} \cancel{+ 7} = 0 + 7$

$x = 7$