# How do you solve 2x^2-13x-7=0 using the quadratic formula?

Apr 16, 2017

$x = 7$ or $x = - \frac{1}{2}$

#### Explanation:

Let's begin with the quadratic formula: x=(-b+- sqrt(b^2-4ac))/(2a

In the equation $2 {x}^{2} - 13 x - 7 = 0$, the a-value equals 2, the b-value equals -13, and the c-value is -7.

We substitute those numbers into our equation, and simplify to find our answer:

$x = \frac{13 \pm \sqrt{169 - 4 \left(2\right) \left(- 7\right)}}{2 \left(2\right)}$ (Substitution)
$x = \frac{13 \pm \sqrt{225}}{4}$ (Simplify)
$x = \frac{13 \pm 15}{4}$ (Simplify)
$x = \frac{28}{4}$ or $x = \frac{- 2}{4}$ (Simplify)
$x = 7$ or $x = - \frac{1}{2}$ (Simplify)