Question

How do you solve `2x^2 - 28x + 98 = 0` using the quadratic formula?

Answer 1

Double root at x = 7

Explanation:

`y = x^2 - 14x + 49 = 0`
`D = d^2 = b^2 - 4ac = 196 - 196 = 0`
There is a double-root at `x = -b/(2a) = 14/2 = 7`