# How do you solve #2x^2-2x-12=0#?

##### 2 Answers

Aug 15, 2016

#### Answer:

#### Explanation:

All the numbers in the equation are even, so divide through by 2.

The factors of 6 which subtract to make 1 are 2 and 2.

If the answer to multiplication is 0, then one of the factors must be 0,

If

If

Aug 15, 2016

#### Answer:

#### Explanation:

The first step is to take out a

#color(blue)"common factor"# of 2.

#rArr2(x^2-x-6)=0# We now require to factorise the

#color(blue)"quadratic"# in the

bracket.Find the factors of - 6 which sum to - 1.

These are - 3 and +2

#rArr2x^2-2x-12=2(x-3)(x+2)=0# Either of the factors (x - 3) , (x +2) can equal zero.

solve :

#x-3=0rArrx=3# solve :

#x+2=0rArrx=-2#