Question

How do you solve `2x^2-3x+10=0`?

Answer 1

Solve `y = 2x^2 - 3x + 10 = 0`

Explanation:

Discriminant `D = b^2 - 4ac = 9 - 80 = - 71 < 0.`
There are no real roots. There are 2 complex roots.