How do you solve 2x^2+3x-2=0?

Jan 17, 2017

$x = \frac{1}{2}$ or $- 2$

Explanation:

$2 {x}^{2} + 3 x - 2 = 0$

Factorise $\to$

$\left(2 x - 1\right) \left(x + 2\right) = 0$

$\therefore$ either $\left(2 x - 1\right) = 0 \to x = \frac{1}{2}$

or $\left(x + 2\right) = 0 \to x = - 2$