How do you solve #2x^2+4x-30 =0#?
Let's apply the quadratic formula:
Therefore, the solutions to the equation are
All the terms in the equation are even, so we can divide by 2 immediately to make the numbers smaller.
Find factors of 15 which subtract (because of -15) to give 2.
The signs will be different (because of -15), there must be more positives. (because of +2)
5 and 3 will work!
Putting each factor equal to 0 gives the solutions: