# How do you solve #2x^2+4x-30 =0#?

##### 2 Answers

#### Explanation:

We have:

Let's apply the quadratic formula:

Therefore, the solutions to the equation are

#### Explanation:

All the terms in the equation are even, so we can divide by 2 immediately to make the numbers smaller.

Try to factor before we use loner methods of the quadratic formula or completing the square.

Find factors of 15 which subtract (because of -15) to give 2.

The signs will be different (because of -15), there must be more positives. (because of +2)

**5 and 3** will work!

Putting each factor equal to 0 gives the solutions: