How do you solve #2x^2 + 5x =0# by factoring?

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Mar 21, 2018

Answer:

#x=0 #
#x=-5/2 #

Explanation:

#2x^2+5=0 #

#x(2x+5)=0 #

therefore...

#x=0 #

and

#2x+5=0 #

#2x=-5 #

#x=-5/2#

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