# How do you solve 2x^2+5x= - 4 using the quadratic formula?

Feb 19, 2016

($- b + \mathmr{and} -$ sqrt(b^2 -4(a)(C)))÷(#2a) quadratic formula must equal zero

# x

${b}^{2}$ ±√b−4ac

$$       2a


#### Explanation:

move 4 to the other side so

$2 {x}^{2} + 5 x + 4 = 0$

$2 {x}^{2} = a$
$5 x = b$
$4 = c$