Question

How do you solve `2x^2 + 6x = 10`?

Answer 1

`x=(-6+- sqrt116) / 4`

Explanation:

1) Begin by setting the equation equal to zero
`2x^2 +6x -10 =0`
Then you can solve the equation using factoring or plugging it into the equation `x = (-b+- sqrt(b^2-4ac))/(2a)`
Since this equation is particularly difficult to factor, we plug the numbers's into the equation sateted previously where
`a=2, b=6, and c=-10`