# How do you solve 2x^2 + 6x = 10?

Apr 17, 2018

$x = \frac{- 6 \pm \sqrt{116}}{4}$
$2 {x}^{2} + 6 x - 10 = 0$
Then you can solve the equation using factoring or plugging it into the equation $x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
$a = 2 , b = 6 , \mathmr{and} c = - 10$