How do you solve #2x^2 + 6x = 10#?

1 Answer
Apr 17, 2018

Answer:

#x=(-6+- sqrt116) / 4 #

Explanation:

1) Begin by setting the equation equal to zero
#2x^2 +6x -10 =0 #
Then you can solve the equation using factoring or plugging it into the equation # x = (-b+- sqrt(b^2-4ac))/(2a) #
Since this equation is particularly difficult to factor, we plug the numbers's into the equation sateted previously where
#a=2, b=6, and c=-10 #