Question

How do you solve `2x^2 + 8x - 3 = 0`?

Answer 1

`x = - 2 +- sqrt22/2`

Explanation:

Use the improved quadratic formula (Google, Yahoo Search)
`D = d^2 = b^2 - 4ac = 64 + 24 = 88` ---> `d = +-2sqrt22`
There are 2 real roots:
`x = -b/(2a) +- d/(2a) = -8/4 +- (2sqrt22)/4 =`
`= -2 +- sqrt22/2`