How do you solve #2x^2 + 9x + 4 = 0# using the quadratic formula?

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Answer 1 · 2016-02-27T07:20:58

#x=( -1)/(2) or x=-4#

Given equation is #2x^2+9x+4=0#
Comparing with #ax^2+bx+c=0#

We get, #a= 2; b=9, c= 4#

#x=( -b+-sqrt(b^2-4ac))/(2a)#

#x=( -9+-sqrt(9^2-4xx2xx4))/(2xx2)#

#x=( -9+-sqrt(81-32))/(4)#

#x=( -9+-sqrt(49))/(4)#

#x=( -9+-7)/(4)#

#x=( -9+7)/(4) or x=( -9-7)/(4)#

#x=( -2)/(4) or x=( -16)/(4)#

#x=( -1)/(2) or x=-4#