How do you solve 2x^2+x-3=0? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Anjali G Nov 27, 2016 x=1,x=-3/2 Explanation: 2x^2+x-3=0 Solve by factoring: 2x^2-2x+3x-3=0 2x(x-1)+3(x-1)=0 (2x+3)(x-1)=0 2x+3=0 2x=-3 x=-3/2 x-1=0 x=1 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 29410 views around the world You can reuse this answer Creative Commons License