Question

How do you solve `2x^2-x-4=10`?

Answer 1

`(1 +- sqrt113)/4`

Explanation:

Use the improved quadratic formula (Socratic Search).
`y = 2x^2 - x - 14 = 0`
`D = d^2 = b^2 - 4ac = 1 + 112 = 113` --> `d = +- sqrt113`
There are 2 real roots:
`x = -b/(2a) +- d/(2a) = 1/4 +- sqrt113/4 = (1 + sqrt113)/4`