# How do you solve (2x - 3)^2 = 1?

Apr 19, 2016

$x = \left\{1 , 2\right\}$

#### Explanation:

${\left(2 x - 3\right)}^{2} = 1$

$\sqrt{{\left(2 x - 3\right)}^{2}} = \sqrt{1}$

2x-3=±1
$\mathmr{if} + 1$
$2 x = 1 + 3$

$2 x = 4$

$x = \frac{4}{2}$

$x = 2$

$\mathmr{if} - 1$

$2 x - 3 = - 1$

$2 x = 2$

$x = 1$