# How do you solve 2x^3 + 4x^2 + 4x + 8 when x = 15?

Sep 26, 2015

The answer is $7718$.

#### Explanation:

Substitute $15$ for $x$.

$2 {x}^{3} + 4 {x}^{2} + 4 x + 8$

$2 \left({15}^{3}\right) + 4 \left({15}^{2}\right) + 4 \left(15\right) + 8 =$

$6750 + 900 + 60 + 8 = 7718$