# How do you solve #2x^3 – 5x^2 – 3x + 2 = 2#?

##### 1 Answer

Jan 21, 2016

#### Explanation:

Begin by subtracting

#2x^3-5x^2-3x=0#

Factor an

#x(2x^2-5x-3)=0#

The quadratic is factorable into

#x(2x+1)(x-3)=0#

Now that you have these three terms being equal to

#x=0#

#2x+1=0" "=>" "x=-1/2#

#x-3=0" "=>" "x=3#