How do you solve #(2x-3)/(x+3)=(3x)/(x+4)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Binayaka C. Aug 11, 2016 # x=-2+2.828i, x=-2-2.828i# Explanation: #(2x-3)/(x+3)=(3x)/(x+4) or (2x-3)(x+4)=3x(x+3) or 2x^2+5x-12=3x^2+9x or x^2+4x+12=0 or (x+2)^2-4+12=0 or (x+2)^2 =-8 or (x+2)=+-sqrt(-8) or (x+2)= 2sqrt2 i or x= -2+2sqrt2 i or x= -2-2sqrt2 i or x=-2+2.828i, x=-2-2.828i#[Ans] Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1249 views around the world You can reuse this answer Creative Commons License