Question

How do you solve `2x+3+x+5=11`?

Answer 1

`x=1`

Explanation:

`"collect terms in x on the left side of the equation and "`
`"numeric values on the right side"`

`rArr3x+8=11larr" collecting like terms on left side"`

`"subtract 8 from both sides"`

`3xcancel(+8)cancel(-8)=11-8`

`rArr3x=3`

`"divide both sides by 3"`

`(cancel(3) x)/cancel(3)=3/3`

`rArrx=1`

`color(blue)"As a check"`

Substitute this value into the left side and if equal to the right side then it is the solution.

`(2xx1)+3+1+5=2+3+1+5=11=" right side"`

`rArrx=1" is the solution"`