How do you solve #2x+3+x+5=11#?

1 Answer
Jun 14, 2017

Answer:

#x=1#

Explanation:

#"collect terms in x on the left side of the equation and "#
#"numeric values on the right side"#

#rArr3x+8=11larr" collecting like terms on left side"#

#"subtract 8 from both sides"#

#3xcancel(+8)cancel(-8)=11-8#

#rArr3x=3#

#"divide both sides by 3"#

#(cancel(3) x)/cancel(3)=3/3#

#rArrx=1#

#color(blue)"As a check"#

Substitute this value into the left side and if equal to the right side then it is the solution.

#(2xx1)+3+1+5=2+3+1+5=11=" right side"#

#rArrx=1" is the solution"#