How do you solve #2x-3x=11#?

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Answer 1 · 2018-03-09T15:34:47

#x = -11#

#2x-3x=-1x#

So

#-1x = 11#

Divide by #-1# on both sides

#x = -11#

Answer 2 · 2018-03-09T15:35:55

#x=-11#

1) Subtract #3x# from #2x#:

#2x-3x=11#

#-x=11#

This can be rewritten as:

#(-1)(x)=11#

2) Multiply both sides by #-1#, to change the L.H.S to #x#:

#-1*-1(x)=-1(11)#

#=> 1(x)=-11#

#=>x=-11#

Thus, solved.