Question

How do you solve `2x²+3x=5` using the quadratic formula?

Answer 1

`- 5/2, 1`

Explanation:

Bring the equation to standard form:

`y = 2x^2 + 3x - 5 = 0`.

Use the improved quadratic formula (Socratic Search)(https://socratic.org/questions/what-is-the-improved-quadratic-formula-in-solving-quadratic-equations?source=search):

`D = d^2 = b^2 - 4ac = 9 + 40 = 49` --> `d = +- 7`

There are 2 real roots:

`x = - b/(2a) +- d/(2a) = - 3/4 +- 7 /4`

`x1 =( - 3 - 7)/4 = - 10/4 = -5/2`

`x2 = (- 3 + 7)/4 = 4/4 = 1`