How do you solve (2x + 4)^2 = 64 ?

Aug 21, 2015

The solutions are
color(blue)(x=-6,x=2

Explanation:

${\left(2 x + 4\right)}^{2} = 64$

Taking the square root of both terms:

$\sqrt{{\left(2 x + 4\right)}^{2}} = \sqrt{64}$

$2 x + 4 = \pm 8$

Solution 1:
$2 x + 4 = + 8$

$2 x + 4 - 4 = + 8 - 4$

$2 x = 4$
color(blue)(x=2

Solution 2:
$2 x + 4 = - 8$

$2 x + 4 - 4 = - 8 - 4$

$2 x = - 12$
color(blue)(x=-6