How do you solve (2x)/(4-x)=x^2/(x-4)? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Deepak G. Aug 13, 2016 x=0 x=-2 Explanation: (2x)/(4-x)=x^2/(x-4) or -(2x)/(x-4)=x^2/(x-4) or x^2=-2x or x^2+2x=0 or x(x+2)=0 or x=0------------------Ans 1 or x+2=0 or x=-2----------------------------Ans 2 Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve 5x-\frac{1}{x}=4? How do you solve -3 + \frac{1}{x+1}=\frac{2}{x} by finding the least common multiple? What is the least common multiple for \frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6} and how do... How do you solve \frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}? How do you solve by clearing the denominator of 3/x+2/x^2=4? How do you solve 2/(x^2+2x+1)-3/(x+1)=4? How do you solve equations with rational expressions 1/x+2/x=10? How do you solve for y in (y+5)/ 2 - y/3 =1? See all questions in Clearing Denominators in Rational Equations Impact of this question 1618 views around the world You can reuse this answer Creative Commons License