# How do you solve 2x+4y=-1 and 4x-3y=-2?

Apr 22, 2016

The solution for the system of equations is:
color(green)(x = - 1/2
color(green)(y =0

#### Explanation:

$2 x + 4 y = - 1$, multiplying by $2$
$\textcolor{b l u e}{4 x} + 8 y = - 2$................equation $\left(1\right)$

$\textcolor{b l u e}{4 x} - 3 y = - 2$.................equation $\left(2\right)$

Solving by elimination:

Subtracting equation $2$ from $1$ :
$\cancel{\textcolor{b l u e}{4 x}} + 8 y = - 2$

$- \cancel{\textcolor{b l u e}{4 x}} + 3 y = + 2$

$11 y = 0$

$y = \frac{0}{11}$

color(green)(y =0

Finding $x$ from the first equation.

$2 x + 4 y = - 1$

$2 x = - 1 - 4 y$

$2 x = - 1 - 4 \cdot 0$

$2 x = - 1$

color(green)(x = - 1/2

Apr 22, 2016

The solution for the system of equations is:
color(green)(x = - 1/2
color(green)(y =0

#### Explanation:

$2 x + 4 y = - 1$, multiplying by $2$
$\textcolor{b l u e}{4 x} + 8 y = - 2$................equation $\left(1\right)$

$\textcolor{b l u e}{4 x} - 3 y = - 2$.................equation $\left(2\right)$

Solving by elimination:

Subtracting equation $2$ from $1$ :
$\cancel{\textcolor{b l u e}{4 x}} + 8 y = - 2$

$- \cancel{\textcolor{b l u e}{4 x}} + 3 y = + 2$

$11 y = 0$

$y = \frac{0}{11}$

color(green)(y =0

Finding $x$ from the first equation.

$2 x + 4 y = - 1$

$2 x = - 1 - 4 y$

$2 x = - 1 - 4 \cdot 0$

$2 x = - 1$

color(green)(x = - 1/2