How do you solve #(2x)/5 + (y/3) = 4#?

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Answer 1 · 2018-03-20T07:17:04

#color(green)(6x + 5y - 60 = 0#

Since there are 2 variables and only one equation given, we can only simplify the equation.

#(2x) / 5 + y / 3 = 4#

Taking L C M for L H S,

#((2x * 3 )+ (y * 5))/15 = 4, " L C M for 3, 5 is 15"#

#(6x + 5 y ) / 15 = 4#

#6x + 5y = 15 * 4 = 60, " cross multiplying"#

#6x + 5y - 60 = 0#