How do you solve #2x² + 5x = -3#?

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Answer 1 · 2016-04-14T09:27:16

The solutions are:
# x = - 1 #

# x = - 3/2#

#2x^2 + 5x = -3#

#2x^2 + 5x + 3 = 0#

The equation is of the form #color(blue)(ax^2+bx+c=0# where:

#a=2, b= 5 , c= 3 #

The Discriminant is given by:

#Delta=b^2-4*a*c#

# = (5)^2-(4* 2 * 3 )#

# = 25 - 24 = 1 #

The solutions are normally found using the formula
#x=(-b+-sqrtDelta)/(2*a)#

#x = ((-5 +-sqrt(1))/(2*2)) = (-5+-1 )/4#

The solutions are:
# x = (-5+1 )/4 = -4 /4 = - 1 #

# x = (-5 - 1 )/4 = -6 /4 = - 3/2#