How do you solve 2x-5y=-19 and 3x+2y =0?

1 Answer
Apr 24, 2018

Answer:

#y=3# and #x=-2#

Explanation:

There are multiple ways to solve simultaneous equations. You can use an "elimination" method, where you remove one of the unknown from the equation or use a "substitution" method. I will use a substitution method, where you substitute one variable with an expression containing the other value.

if

#3x+2y=0#

then

#y=((-3x)/2)#

Substitute this value for #y# into the other equation:

#2x-5y=-19#

#2x-5((-3x)/2)=-19#

#2x+(15x)/2=-19#

#4x+15x=-38#

#19x=-39#

#x=-2#

So, using any of the two equations we can find #y#:

#2(-2)-5y=-19#

#-4-5y=-19#

#-5y=-15#

#y=3#