How do you solve $-2x + 6y = 19$ and $10x – 30y = -15$ using substitution?

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Answer 1 · 2018-04-26T11:10:10

Parallel lines (equal slope). (No solution)

$-2 x+6 y=19 (1) and 10 x -30 y= -15 (2)$ Multiplying

equation (1) by $(-5)$ we get $10 x -30 y= 95$ . Slope of

both the lines are equal , so they are parallel lines.

Therefore "No solution" # [Ans]

How do you solve -2x + 6y = 19-2x + 6y = 19 and 10x – 30y = -1510x – 30y = -15 using substitution?