How do you solve #2x-6y=40# and #7x+60=y# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Shwetank Mauria Jun 23, 2016 #x=-10# and #y=-10# Explanation: As #7x+60=y#, we can write #2x-6y=40# by substituting value of #y# as #2x-6(7x+60)=40# or #2x-42x-360=40# or #-40x=40+360=400# Hence #x=400/-40=-10# and #y=7xx(-10)+60=-10# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1283 views around the world You can reuse this answer Creative Commons License