# How do you solve (2x+8)(3x-6)=0 using any method?

May 4, 2017

$x = - 4 \mathmr{and} x = 2$

#### Explanation:

Expand the equation from the brackets

$\left(2 x + 8\right) \left(3 x - 6\right) = 0$
(color(red)(2x)+8)(color(red)(3x)-6) Multiply the highest power of $x$ first
(color(red)(2x)+8)(3x$\textcolor{red}{- 6}$) Next multiply by the next highest power

(2xcolor(blue)(+8)($\textcolor{b l u e}{3 x}$-6) Multiply by the highest power
(2xcolor(blue)(+8)(3x$\textcolor{b l u e}{- 6}$) Multiply by next highest power.

Therefore,
$6 {x}^{2} - 12 x + 24 x - 48 = 0$
$6 {x}^{2} + 12 x - 48$=0 ------------------Divide the equation by 6
${x}^{2} + 2 x - 8 = 0$ --------------------------Simplify the equation
$\left(x + 4\right) \left(x - 2\right) = 0$
$x + 4 = 0 \mathmr{and} x - 2 = 0$
$x = - 4 \mathmr{and} x = 2$