How do you solve -2x -8y = 4 and x+ 16y = 22?
1 Answer
Sep 6, 2015
Explanation:
Your system of equations looks like this
#{(-2x - 8y = 4), (x + 16y = 22) :}#
Multiply the second equation by
#{(-2x - 8y = 4), (x + 16y = 22 | * (2)) :}#
#{(-2x - 8y = 4), (2x + 32y = 44) :}#
Add these two equations by taking the left-hand sides and the right-hand sides separately
#-color(red)(cancel(color(black)(2x))) - 8y + color(red)(cancel(color(black)(2x))) + 32y = 4 + 44#
#24y = 48 implies y = 48/24 = 2#
Take this value of
#x + 16 * (2) = 22#
#x + 32 = 22 implies x = -10#
The solution set for this system will be
#{(x = -10), (y = 2) :}#