How do you solve #(2x)/9 + 1/3 = 5#?

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Answer 1 · 2016-05-08T19:29:51

Get rid of the fractions first, then solve for the unknown.

#x = 21#

Whenever an equation has fractions, it is possible to get rid of them by multiplying each term by the LCM of the denominators.

#(2x)/9 + 1/3 = 5 " " xx9#

#color(red)9xx(2x)/9 + color(red)9xx1/3 = color(red)9xx5#

#cancel9xx(2x)/cancel9 + cancel9^3xx1/cancel3 = 9xx5#

#2x + 3 = 45#

#2x = 45-3#

#2x = 42#

#x = 21#