How do you solve # 2x(x - 1) = 3#? Algebra Linear Equations Multi-Step Equations with Like Terms 1 Answer Ratnesh Bhosale Mar 26, 2016 #x=[1+-sqrt(13)]/4# Explanation: #2x(x-1)=3# #4x^2-2x=3# #4x^2-2x-3=0# Comparing with #ax^2+bx+c=0# we get, #a=4, b=-2,c=-3# By Formula method, #x=[-b+-sqrt(b^2-4ac)]/(2a)# #x=[-(-2)+-sqrt((-2)^2-4xx4xx-(3))]/(2xx4)# #x=[2+-sqrt(4+48)]/(8)# #x=[2+-sqrt(52)]/(8)# #x=[2+-sqrt(4xx13)]/(8)# #x=[2+-sqrt(4xx13)]/(8)# #x=[2+-2sqrt(13)]/(8)# #x=(2[1+-sqrt(13)])/8# #x=[1+-sqrt(13)]/4# Answer link Related questions How do you solve multi step equations by combining like terms? How do you solve multi step equation #w + w + 12 = 40#? How do you solve #3p + 4p + 37 = 79#? How do you solve for f: #f-1+2f+f-3=-4#? How do you combine like terms? How do you combine like terms for #-7mn-2mn^2-2mn + 8#? How do you combine like terms for #3x^2 + 21x + 5x + 10x^2#? What is a term? How do you solve #3v+5-7v+18=17#? How do you solve for x in #5x + 7x = 72#? See all questions in Multi-Step Equations with Like Terms Impact of this question 2186 views around the world You can reuse this answer Creative Commons License