# How do you solve 2y+18=12-6(y+7)?

Oct 28, 2015

$y = - 8$

#### Explanation:

Expanding the brackets:
$2 y + 18 = 12 - 6 y - 42$

Adding the constants on the right and removing the constant from the left.

Subtract 18 from both sides
$\left(2 y + 18\right) - 18 = \left(- 6 y - 30\right) - 18$

$2 y = - 6 y - 48$

Moving the 'y' term from the right

Add $6 y$ to both sides

$\left(2 y\right) + 6 y = \left(- 6 y - 48\right) + 6 y$

$8 y = - 48$

To remove the 8 from $8 y$

Divide both sides by 8 (divide by 8 is the same multiply by $\frac{1}{8}$)
$\frac{8 y}{8} = \frac{- 48}{8}$

$\frac{8}{8} y = - 8$

$y = - 8$