# How do you solve 2y^2+6=y^2?

May 23, 2015

$y = \sqrt{6} i = i \sqrt{6}$

Problem: Solve $2 {y}^{2} + 6 = {y}^{2}$.

Subtract $6$ from both sides of the equation.

$2 {y}^{=} {y}^{2} - 6$

Subtract ${y}^{2}$ from both sides.

${y}^{2} = - 6$

Take the square root of both sides.

$y = \sqrt{- 6}$ =

$y = \sqrt{6} i = i \sqrt{6}$