How do you solve 2y = 4x - 16  and 5y = 4x + 8?

May 3, 2016

Okay we will solve this step by step

Let $2 y = 4 x - 16$ be equation number 1
and $5 y = 4 x + 8$ be equation number 2

$4 x$ is same in both equations that is to say has same coefficient $4 x$

So we will subtract both of them
$+ 5 y = + 4 x + 8$
$- 2 y = - 4 x + 16$
This results in
$3 y = 24$
$y = 8$ Substituting this value in equation number 2

$5 \left(8\right) = 4 x + 8$
$40 = 4 x + 8$
$40 - 8 = 4 x$
$32 = 4 x$
$\frac{32}{4} = x$
$8 = x$

So we get $x = 8$ and $y = 8$

Cheers