How do you solve #2z^2 + 20z = 0#?

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Answer 1 · 2017-01-25T14:58:42

See the entire solution process below:

First, factor the left side of the equation:

#2z(z + 10) = 0#

Next solve each term for #0#:

Solution 1)

#2z = 0#

#(2z)/color(red)(2) = 0/color(red)(2)#

#(color(red)(cancel(color(black)(2)))z)/cancel(color(red)(2)) = 0#

#z = 0#

Solution 2)

#z + 10 = 0#

#z + 10 - color(red)(10) = 0 - color(red)(10)#

#z + 0 = -10#

#z = -10#

The solution is: #z = 0# and #z = -10#