# How do you solve 3(1+x)=2[3(x+2)-(x+1)]?

Jul 16, 2016

$x = - 7$

#### Explanation:

Start by removing the brackets - in the term on the right, start inside the square brackets first.

$3 \left(1 + x\right) = 2 \left[3 \left(x + 2\right) - \left(x + 1\right)\right]$

$3 + 3 x = 2 \left[3 x + 6 - x - 1\right]$

$3 + 3 x = 2 \left(2 x + 5\right)$

$3 + 3 x = 4 x + 10$

$3 - 10 = 4 x - 3 x$

$- 7 = x$