Question

How do you solve `3/2 - 1/(x-5) = -2/(2x - 10)`?

Answer 1

I found no solution! The equation is not true.

Explanation:

We can write it as:
`3/2-1/(x-5)=-2/(2(x-5))`
`(3(x-5)-2)/cancel((2(x-5)))=-2/cancel((2(x-5)))`
`3x-15-2=-2`
`3x=15`
`x=15/3=5`
BUT
`x=5` makes both denominators equal to zero!