How do you solve #3^(2a)=3^(-a)#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Nov 2, 2016 #a=0# Explanation: #3^(2a)=3^(-a)=1/3^a# i.e. #3^(2a)xx3^a=1=3^0# or #3^(2a+a)=3^0# Hence, #3a=0# and #a=0/3=0# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 4255 views around the world You can reuse this answer Creative Commons License