How do you solve #3(2p + 1) + 4(2p-3) = 2p-15#?

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Answer 1 · 2016-05-30T06:34:14

#p=-1/2#

#3(2p+1)+4(2p-3)=2p-15#

#hArr3*2p+3*1+4*2p-4*3=2p-15#

#hArr6p+3+8p-12=2p-15#

#hArr6p+3-3+8p-12+12-2p=2p-2p-15-3+12#

#hArr6pcancel(+3-3)+8pcancel(-12+12)-2p=cancel(2p-2p)-15-3+12#

#hArr6p+8p-2p=-15-3+12#

#hArr12p=-6#

#hArr12pxx1/12=-6/12=-(6xx1)/(6xx2)#

#hArr p=-1/2#