Question

How do you solve `3/(2x-1) - 4/(3x-1) = 1`?

Answer 1

`3(3x-1)-4(2x-1)=1(2x-1)(3x-1) ->9x-3-8x+4=6x^2-5x+1`
`0=6x^2-6x ->6x(x-1)=0,6x=0 or x-1 = 0, x=0 or x=1`

Explanation:

Multiply everything on both sides by the common denominator then put everything on one side and solve for x