How do you solve 3|2y-5|=27 and find any extraneous solutions?

Jul 5, 2016

$y = 7 , \mathmr{and} , - 2$

Explanation:

$3 | 2 y - 5 | = 27 \Rightarrow | 2 y - 5 | = 9 \Rightarrow 2 y - 5 = \pm 9$

Case I$: 2 y - 5 = + 9 \Rightarrow 2 y = 14 \Rightarrow y = 7.$

Case II $: 2 y - 5 = - 9 \Rightarrow 2 y = - 4 \Rightarrow y = - 2$

These values of $y$ satisfy the given eqn. Hence, the soln.