How do you solve #3( 3m - 2) = 2( 2m + 3)#?

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Answer 1 · 2018-01-26T21:19:33

#m=12/5#

Use distributive property. multiply the number in front of the parenthesis with each number inside the parenthesis.

#3*3m= 9m#

#3 * (-2)=6#

#2*2m=4m#

#2*3=6#

The equation now is

#9m-6=4m+6#

The next step is to add #6# on the left side and on the right side. This will get rid of the #-6# on the left side. Your new equation is

#9m=4m+12#

Then you are going to subtract #4m# from both sides. This will give you

#5m=12#

Divide both sides by #5#

#m = 12/5#