How do you solve #3|3q-2|=21#?

1 Answer
Feb 9, 2017

Answer:

#q=3" or " q=-5/3#

Explanation:

Isolate the #color(blue)"absolute value"# by dividing both sides of the equation by 3

#cancel(3)^1/cancel(3)^1|3q-2|=21/3#

#rArr|3q-2|=7#

There are 2 solutions to the equation.

#"Solve "3q-2=color(red)(+-)7#

#color(blue)"Solution 1"#

#3q-2=color(red)(+7)rArr3q=7+2=9rArrq=9/3=3#

#color(blue)"Solution 2"#

#3q-2=color(red)(-7)rArr3q=-7+2=-5rArrq=-5/3#

#color(blue)"As a check"#

Substitute these values into the left side and if equal to the right side then they are the solutions.

#• x=3to3|9-2|=3xx7=21#

#• x=-5/3to3|-5-2|=3xx|-7|=3xx7=21#

#rArrx=3" or " x=-5/3" are the solutions"#